CSP练习

201912-1 报数


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n=int(input())
a=[0 for i in range(4)]
i,j=1,1
while(j<=n):
    if(i%7==0 or ('7' in str(i))):#7的倍数或者含有7则跳过
        a[(i-1)%4]+=1#跳过次数加1
        j-=1#不计被跳过的数
    i+=1#下一个人
    j+=1#下一个数
for i in a:
    print(i)
66
7
5
11
5

201912-2 回收站选址



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class Point:
    def __init__(self,x,y,w=0,a=0,s=0,d=0,score=0):
        self.x,self.y,self.w,self.a,self.s,self.d,self.score=x,y,w,a,s,d,score
    def newscore(self,p):#四对角得分
        if(self.x+1==p.x and self.y+1==p.y):
            self.score+=1
            p.score+=1
        elif(self.x+1==p.x and self.y-1==p.y):
            self.score+=1
            p.score+=1
        elif(self.x-1==p.x and self.y+1==p.y):
            self.score+=1
            p.score+=1
        elif(self.x-1==p.x and self.y-1==p.y):
            self.score+=1
            p.score+=1
        else:
            pass

    def begood(self,p):#上下左右
        if(self.x+1==p.x and self.y==p.y):
            self.d+=1
            p.a+=1
        elif(self.x-1==p.x and self.y==p.y):
            self.a+=1
            p.d+=1
        elif(self.x==p.x and self.y+1==p.y):
            self.w+=1
            p.s+=1
        elif(self.x==p.x and self.y-1==p.y):
            self.s+=1
            p.w+=1
        else:
            pass
    def good(self):#是否上下左右满足
        if(self.w==1 and self.a==1 and self.s==1 and self.d==1):
            return True
        

s=int(input())
p=[]
for i in range(s):
    s=input().split()
    tempP=Point(int(s[0]),int(s[1]))
    for eachp in p:
        dx=eachp.x-tempP.x
        dy=eachp.y-tempP.y
        if(not eachp.good() and dx*dx+dy*dy==1):
            eachp.begood(tempP)
        if(eachp.score!=4 and dx*dx+dy*dy==2):
            eachp.newscore(tempP)

    p.append(tempP)

ans=[0,0,0,0,0]
for i in p:
    if(i.good()):
        ans[i.score]+=1

for i in ans:
    print(i)
7
1 2
2 1
0 0
1 1
1 0
2 0
0 1
0
0
1
0
0

201912-3 化学方程式



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//样例：
11
H2+O2=H2O
2H2+O2=2H2O
H2+Cl2=2NaCl
H2+Cl2=2HCl
CH4+2O2=CO2+2H2O
CaCl2+2AgNO3=Ca(NO3)2+2AgCl
3Ba(OH)2+2H3PO4=6H2O+Ba3(PO4)2
3Ba(OH)2+2H3PO4=Ba3(PO4)2+6H2O
4Zn+10HNO3=4Zn(NO3)2+NH4NO3+3H2O
4Au+8NaCN+2H2O+O2=4Na(Au(CN)2)+4NaOH
Cu+As=Cs+Au
//结果：
N
Y
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N
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def chemistry(x):
    each=x.split('+') #拆成每个化学式
    res={}#化学元素字典
    for item in each:
        i=0
        num=""#存储每个化学式前面的数字
        if(48<=ord(item[i])<=57):#如果开始是数字
            num+=item[i]
            i+=1
            while(i<len(item)-1 and 48<=ord(item[i])<=57):
                num+=item[i]
                i+=1
        n=1 if num=="" else int(num)
        #化学式前面没有数字，代表为1
        re=single(item[i:],n)
        for key in re:
            res[key]=res.get(key,0)+re[key]
    return res
    
def single(item,m):
    res={}#化学元素字典
    i=0
    s=""
    num=""
    while(i<len(item)):
        if(item[i]=="("):
            p=1
            for j in range(i+1,len(item)):
                if(item[j]=="("):
                    p+=1
                elif (item[j]==")"):
                    p-=1
                    index=j
                if(p==0):
                    break
            k=i+1#第一个左括号之后的位置
            i=index#括号结束的位置
            if(i<len(item)-1 and 48<=ord(item[i+1])<=57):#如果是数字
                num+=item[i+1]
                i+=1
                while(i<len(item)-1 and 48<=ord(item[i+1])<=57):
                    num+=item[i+1]
                    i+=1
            n=1 if num=="" else int(num)
            re=single(item[k:index],n*m)
            for key in re:
                res[key]=res.get(key,0)+re[key]
        elif(65<=ord(item[i])<=90):#如果是大写字母
            s+=item[i]
            if(i<len(item)-1 and 97<=ord(item[i+1])<=122):#如果是小写字母
                s+=item[i+1]
                i+=1
            if(i<len(item)-1 and 48<=ord(item[i+1])<=57):#如果是数字
                num+=item[i+1]
                i+=1
                while(i<len(item)-1 and 48<=ord(item[i+1])<=57):
                    num+=item[i+1]
                    i+=1
            n=1 if num=="" else int(num)
            res[s]=res.get(s,0)+m*n#这个化学元素个数，初始为0
        num=""
        s=""
        i+=1
    return res

def main():
    n=int(input())
    expressions=[]
    for i in range(n):
        expressions.append(input())
    for item in expressions:
        express=item.split("=")#每个表达式从等号分开
        left,right=express[0],express[1]
        ans1=chemistry(left)
        ans2=chemistry(right)
        if(ans1==ans2):
            print('Y')
        else:
            print('N')

main()
11
H2+O2=H2O
2H2+O2=2H2O
H2+Cl2=2NaCl
H2+Cl2=2HCl
CH4+2O2=CO2+2H2O
CaCl2+2AgNO3=Ca(NO3)2+2AgCl
3Ba(OH)2+2H3PO4=6H2O+Ba3(PO4)2
3Ba(OH)2+2H3PO4=Ba3(PO4)2+6H2O
4Zn+10HNO3=4Zn(NO3)2+NH4NO3+3H2O
4Au+8NaCN+2H2O+O2=4Na(Au(CN)2)+4NaOH
Cu+As=Cs+Au
N
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Y
N

201912-4 区块链





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201912-5 魔数








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